Ask Question
29 December, 20:49

A small sculpture made of brass (rho brass = 8470 kg/m 3) is believed to have a secret central cavity. The weight of the sculpture in air is 15.76 N. When it is submerged in water, the weight is 13.86 N. What is the volume of the secret cavity?

+1
Answers (1)
  1. 29 December, 21:18
    0
    Volume of secret cavity = 4 x 10⁻⁶m³

    Explanation:

    The weight of the sculpture in air is 15.76 N

    Mass of the sculpture = 1.61 kg

    Mass = Volume x Density

    1.61 = V x 8470

    Volume of brass = 1.90 x 10⁻⁴ m³

    When it is submerged in water, the weight is 13.86 N.

    That is

    Weight of sculpture - Weight of water displaced = 13.86 N

    15.76 - Weight of water displaced = 13.86

    Weight of water displaced = 1.9 N

    Mass of water displaced = 0.194 kg

    Mass = Volume x Density

    0.194 = V x 1000

    Volume of water displaced = 1.94 x 10⁻⁴ m³

    Volume of secret cavity = Volume of water displaced - Volume of brass material

    Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A small sculpture made of brass (rho brass = 8470 kg/m 3) is believed to have a secret central cavity. The weight of the sculpture in air ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers