2 kg of air is at T = 120degreeC and P = 3.5 bar. Find the volume.

The Volume is V = 644.89 L

Explanation:

m = 2 kg

T = 120 º C = 393.15 K

P = 3.5 bar = 3.45 atm

R = 0.08205746 atm L / K mol

M = 0.029 Kg / mol

n = m/M

n = 68.96 moles

p*V = m*R*T

V = m*R*T/p

V=644.89 L