Ask Question
27 September, 01:45

A 0.500-kilogram cart traveling to the right on a horizontal, frictionless surface at 2.20 meters per second collides head on with a 0.800-kilogram cart moving to the left at 1.10 meters per second. What is the magnitude ofthe total momentum of the two-cart system after the collision?

+3
Answers (1)
  1. 27 September, 02:01
    0
    Consider the motion towards right as positive and motion towards left as negative.

    m₁ = mass of the cart moving to right = 0.500 kg

    v₁ = initial velocity before collision of the cart moving towards right = 2.2 m/s

    m₂ = mass of cart moving to left = 0.800 kg

    v₂ = initial velocity before collision of the cart moving towards left = - 1.1 m/s

    initial momentum of the system of carts before the collision is given as

    P₁ = m₁ v₁ + m₂ v₂

    P₁ = (0.500) (2.2) + (0.800) ( - 1.1)

    P₁ = 0.22 kg m/s

    P₂ = momentum of system of carts after collision

    As per conservation of momentum,

    Momentum of system of carts after collision = Momentum of system of carts before collision

    P₂ = P₁

    P₂ = 0.22 kg m/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 0.500-kilogram cart traveling to the right on a horizontal, frictionless surface at 2.20 meters per second collides head on with a ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers