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29 November, 14:23

In a vacuum, two particles have charges of q1 and q2, where q1 = + 4.2C. They are separated by a distance of 0.31 m, and particle 1 experiences an attractive force of 4.5 N. What is the value of q2, with its sign?

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  1. 29 November, 14:42
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    11.44pC.

    Explanation:

    F = kq1q2/r^2

    q2 = Fr^2/kq1

    = 4.5 x 0.31^2/4.2x 9 x 10^9

    = 1.144 x 10^-11C

    = 11.44pC

    The sign is minus since they attracted to each other
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