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22 February, 16:13

Find the moment of inertia Ix of particle a with respect to the x axis (that is, if the x axis is the axis of rotation), the moment of inertia Iy of particle a with respect to the y axis, and the moment of inertia Iz of particle a with respect to the z axis (the axis that passes through the origin perpendicular to both the x and y axes). Express your answers in terms of m and r separated by commas. Ix, Iy, Iz =

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  1. 22 February, 16:31
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    Ix, Iy, Iz = mr²,9mr²,10mr²

    Explanation:

    The Question has some missing details.

    To solve this question, I'll make the following assumptions.

    Distance of particle x = r

    Distance of particle y = 3r

    Given

    The mass of each particles = m

    The moment of inertia is calculated by adding product of mass" of each particle with the "square of its distance from the axis of the rotation".

    Ix = m * (r) ² = mr²

    Iy = m (3r) ² = m * 9r² = 9mr²

    The distance of z from the axis is r² + (3r) ²

    So, Iz = m (r² + (3r) ²)

    Iz = m (r² + 9r²)

    Iz = m (10r²)

    Iz = 10mr²

    So, we have

    Ix, Iy, Iz = mr²,9mr²,10mr²
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