circular saw blade of diameter 0.190 m starts from rest. In a time interval of 5.80 s it accelerates with constant angular acceleration to an angular velocity of 145 rad/s. Part A Find the angular acceleration. Express your answer in radians per second squared. α = nothing rad/s2 Request Answer Part B Find the angle through which the blade has turned. Express your answer in radians. θ = nothing rad Request Answer Provide Feedback

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Physics

5 December, 20:09

circular saw blade of diameter 0.190 m starts from rest. In a time interval of 5.80 s it accelerates with constant angular acceleration to an angular velocity of 145 rad/s. Part A Find the angular acceleration. Express your answer in radians per second squared. α = nothing rad/s2 Request Answer Part B Find the angle through which the blade has turned. Express your answer in radians. θ = nothing rad Request Answer Provide Feedback

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Brylee Clayton · Answer 1

We shall apply newton's law equation valid for rotational motion.

ωt = ω₀ + α t where ωt is angular velocity after time t, ω₀ is angular velocity at t = 0 and α is angular acceleration

145 = 0 + α x 5.8

α = 25 rad / s²

B)

θ = ω₀ t + 1/2 α t²

= 0 +.5 x 25 x 5.8 x 5.8

= 420.5 rad.