A tennis player player receives a shot with the ball (.06kg) travelling horizontally at 50.0 m/s and returns the shot with the ball travelling horizontally at 40.0 m/s in the opposite direction. a) What is the impulse delivered to the ball by the tennis racquet? b) What work does the racquet do on the ball?

Question

Dana

Physics

11 August, 17:47

A tennis player player receives a shot with the ball (.06kg) travelling horizontally at 50.0 m/s and returns the shot with the ball travelling horizontally at 40.0 m/s in the opposite direction. a) What is the impulse delivered to the ball by the tennis racquet? b) What work does the racquet do on the ball?

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Answers (1)

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Talon Hicks · Answer 1

Let:

m - 0.0600Kg

v1 - + 50.0 m/s

v2 - - 42 m/s

a)

momentum1 - momentum2 = impulse

p1 - p2 = Ft

m (v1 + v2) = Ft

Ft = 0.54 N-s

b)

Work is traditionally force times distance but an easy way to get through this one is to think logically and keep your units straight:

The racket creates an overall velocity of 90 m/s for the ball:

W = (Ft) * (V)

W=0.54 N-s * 90 m/s

W=48.6 N-m = 48.6 J