A 66-kg skier starts from rest at the top of a 1200-m-long trail which drops a total of 170 m from top to bottom. at the bottom, the skier is moving 11 m/s.

Question

Bitsy

Physics

25 September, 11:34

A 66-kg skier starts from rest at the top of a 1200-m-long trail which drops a total of 170 m from top to bottom. at the bottom, the skier is moving 11 m/s.

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Marlene Morales · Answer 1

I believe this question ask for the energy dissipated by friction.

The overall energy equation for this is:

F = PE - KE

where F is friction loss, PE is potential energy = m g h, KE is kinetic energy = 0.5 m v^2

F = 66 kg * 9.8 m/s^2 * 170 m - 0.5 * 66 kg * (11 m/s) ^2

F = 105,963 J ~ 106,000 J