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1 November, 07:31

A spring has a spring of 120 newtons per meter. calculate the elastic potential energy stored in the spring when it is stretched 2.0 centimeters ...?

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  1. 1 November, 07:49
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    We know that force for a linear spring is equal to F=kx. Since energy is the potential to do work, and the spring is assumed to be perfectly elastic. Work can be written as:

    W = F (integral sign) d x

    Therefore,

    W=k (Δx) ^2 / 2

    W = F Δx / 2

    W = 120 (2.0) / 2

    W = 120
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