A simple pendulum consists of a ball connected to one end of a thin brass wire. The period of the pendulum is 2.51 s. The temperature rises by 142 C°, and the length of the wire increases. Determine the change in the period of the heated pendulum.

Question

Jacquelyn Meza

Physics

7 November, 15:37

A simple pendulum consists of a ball connected to one end of a thin brass wire. The period of the pendulum is 2.51 s. The temperature rises by 142 C°, and the length of the wire increases. Determine the change in the period of the heated pendulum.

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Answers (1)

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Konnor Carpenter · Answer 1

The period of the heated pendulum is of T = 2.5124 seconds.

Explanation:

α = 18 * 10⁻⁶ 1/ºC

T1 = 2.51 s

T2=?

g = 9.8 m/s²

ΔTemp = 142ºC

L1 = (T1/2π) ² * g

L1 = 1.563m

L2 = α * L1 * ΔTemp + L1

L2 = 1.567 m

T2 = 2π * √ (L2/g)

T2 = 2.5124 sec