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7 November, 15:37

A simple pendulum consists of a ball connected to one end of a thin brass wire. The period of the pendulum is 2.51 s. The temperature rises by 142 C°, and the length of the wire increases. Determine the change in the period of the heated pendulum.

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  1. 7 November, 15:53
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    The period of the heated pendulum is of T = 2.5124 seconds.

    Explanation:

    α = 18 * 10⁻⁶ 1/ºC

    T1 = 2.51 s

    T2=?

    g = 9.8 m/s²

    ΔTemp = 142ºC

    L1 = (T1/2π) ² * g

    L1 = 1.563m

    L2 = α * L1 * ΔTemp + L1

    L2 = 1.567 m

    T2 = 2π * √ (L2/g)

    T2 = 2.5124 sec
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