12. A boy of mass 50 kg running 5m/s jumps on to a 20kg trolley

travelling in the same direction at 1.5m/s. Find their common

velocity. Assume that there is no external unbalanced force

working in the horizontal direction.

Question

7 December, 03:44

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Answers (1)

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Clarence Wolf · Answer 1

4 m/s

Explanation:

Momentum is conserved.

m₁ v₁ + m₂ v₂ = (m₁ + m₂) v

(50) (5) + (20) (1.5) = (50 + 20) v

v = 4

The final velocity is 4 m/s.

12. A boy of mass 50 kg running 5m/s jumps on to a 20kg trolleytravelling in the same direction at 1.5m/s. Find their commonvelocity. Assume that there is no external unbalanced forceworking in the horizontal direction.