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29 August, 17:52

A 2.6 kg object is accelerated from rest to a

speed of 22 m/s in 22 s.

What average force was exerted on the ob-

ject during this period of acceleration?

+1
Answers (1)
  1. 29 August, 17:56
    0
    2.6 N

    Explanation:

    Given:

    v₀ = 0 m/s

    v = 22 m/s

    t = 22 s

    Find: a

    v = at + v₀

    (22 m/s) = a (22 s) + (0 m/s)

    a = 1 m/s²

    Newton's second law:

    F = ma

    F = (2.6 kg) (1 m/s²)

    F = 2.6 N
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