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3 December, 20:56

A soccerball is kicked straight out from a hill at 15 m/s and lands 42m away. how tall is the hill

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  1. 3 December, 21:23
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    The height of the hill is, h = 38.42 m

    Explanation:

    Given,

    The horizontal velocity of the soccer ball, Vx = 15 m/s

    The range of the soccer ball, s = 42 m

    The projectile projected from a height is given by the formula

    S = Vx [Vy + √ (Vy² + 2gh) ] / g

    Therefore,

    h = S²g/2Vx² (Since Vy = 0)

    Substituting the values

    h = 42² x 9.8 / (2 x 15²)

    = 38.42 m

    Hence, the height of the hill is, h = 38.42 m
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