How many joules are released as 10.0g of steam at 110℃ cools to produce water at 25℃?

26,000 J

Explanation:

Heat released when the steam is cooled:

q = mCΔT

q = (10.0 g) (2.02 J/g/K) (100℃ - 110℃)

q = - 202 J

Heat released during condensation (gas to liquid):

q = mL

q = (10.0 g) (-2260 J/g)

q = - 22,600 J

Heat released when the liquid water is cooled:

q = mCΔT

q = (10.0 g) (4.184 J/g/K) (25℃ - 100℃)

q = - 3138 J

Total heat released:

q = - 202 J - 22,600 J - 3138 J

q = 25,940 J

Rounded to two significant figures, 26,000 J of heat are released.