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3 March, 10:48

A car and driver weighing 7130 N passes a sign stating ... ?

"Bridge Out 32 m Ahead." She slams on the brakes, and the car decelerates at a constant rate of 13.8 m/s^2. The acceleration of gravity is 9.8 m/s^2.

What is the magnitude of the work done stopping the car if the car just stops in time to avoid diving into the water?

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  1. 3 March, 11:02
    0
    321 280 J

    Explanation:

    Work done = force * distance

    The distance is 32 m

    The force can be calculated using the second law of motion

    F = ma = (7130 N : 9.8 m/s²) * 13.8 m/s² = 10 040 N

    Work done = force * distance

    = 10 040 N * 32 m

    = 321 280 J
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