A rotating wheel requires 7.00 s to rotate 28.0 revolutions. its angular velocity at the end of the 7.00-s interval is 96.0 rad/s. what is the constant angular acceleration (in rad/s) of the wheel?

Question

Veronica Reeves

Physics

13 September, 00:24

A rotating wheel requires 7.00 s to rotate 28.0 revolutions. its angular velocity at the end of the 7.00-s interval is 96.0 rad/s. what is the constant angular acceleration (in rad/s) of the wheel?

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Answers (1)

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Jaylen · Answer 1

We know: θ = ωo t + 1/2*α*t^2

so, α = 2 * (θ - ωo t) / t^2

Given: angular velocity = 96.0 rad/sectime = 7 secangular distance travelled = 28 rev

We know, In one revolution it completes 360 degrees = 6.28319 radangular distance traveled = 28 rev * 6.28319 rad

So, angular acceleration = 2 * (28*6.28 - 96*7) / 7^2 = - 20.25 rad/sec^2