Ask Question
24 September, 18:27

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3, length 78.4 cm and diameter 2.30 cm from a storage room to a machinist. Calculate the weight of the rod, w. Assume the free-fall acceleration is g

+2
Answers (1)
  1. 24 September, 18:36
    0
    24.9 N

    Explanation:

    Parameters Given:

    Length of cylinder, h = 78.4 cm = 0.784 m

    Diameter of cylinder = 2.3 cm = 0.023 m

    Radius of cylinder, r = 0.0115m

    Density of rod = 7800 kg/m³

    Desnity is given as:

    Density = mass/volume

    Volume of cylindrical rod is:

    Volume = pi * r² * h

    = 3.142 * 0.0115² * 0.784

    = 0.00326 m³

    Therefore, mass can be gotten:

    Mass = Density * volume

    Mass = 7800 * 0.000326

    Mass = 2.54 kg

    Weight is given as:

    Weight = mass * acceleration due to gravity

    Weight = 2.54 * 9.8

    Weight = 24.9 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3, length 78.4 cm and diameter 2.30 cm from a storage ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers