A piano tuner stretches a steel piano wire with a tension of 765 n. the steel wire has a length of 0.900 m and a mass of 6.75 g. part a what is the frequency f1 of the string's fundamental mode of vibration?

To solve for this we need to find µ

So the formula is µ = m/L =.00675/0.900 = 0.0075 kg/m

Speed of wave u = √[T/µ] = √[765/µ] = 319.4 m/s

f1 is now computed by (1/2L) * u

So plugging in our values, (1/2*.9000m) * 0.0075 kg/m = 177.4 Hz