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5 October, 00:30

if two objects are moved closer together so that the distance between them is one-third the original distance what is the gravitational force after the object is moved

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  1. 5 October, 00:38
    0
    let the mass of the two objects be m₁ and m₂ respectively and the distance between the two objects be "r₁" initially.

    the gravitational force between the two objects initially is then given as

    F₁ = G m₁ m₂ / r₁² eq-1

    where G = universal gravitational constant

    when the objects are moved closer and the distance between the objects become one third of the original distance, hence

    r₂ = distance after objects moved closer = r₁/3

    new gravitational force between the objects after they are moved closed is given as

    F₂ = G m₁ m₂ / r₂² eq-2

    dividing eq-2 by eq-1

    F₂/F₁ = (G m₁ m₂ / r₂²) / (G m₁ m₂ / r₁²)

    F₂/F₁ = r₁²/r₂²

    we know that, r₂ = r₁/3

    hence

    F₂/F₁ = r₁² / (r₁/3) ²

    F₂/F₁ = 9

    F₂ = 9 F₁

    hence the gravitational force becomes nine times its initial value
  2. 5 October, 00:55
    0
    Answer: D

    Explanation:

    Edge nuity
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