The drawings show three situations in which a positively charged particle is moving through a uniform magnetic field B with a velocity v. For each situation, what is the direction of the magnetic force F exerted on the particle?

Case A: - x axis

Case B: - x axis

Case C: no force as the direction of v and B are parallel.

Explanation:

Solution:

- The direction of Force exerted by the magnetic field B with a moving charge q with a velocity of v is given by an expression:

F = q * (v x B)

- Where F: force vector exerted by the field

v: velocity vector of charged particle q.

B: magnetic field direction

- The cross product of v with B:

We will use right hand rule in which our fingers curl from v to B, the direction of the thumb denotes the direction of applied force. Hence,

Case A: - x axis

Case B: - x axis

Case C: no force as the direction of v and B are parallel.