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14 September, 01:57

2) A particle of mass 19 g moves in a circle of radius

0.44 m. The kinetic energy of the particle is 3.7 J. What

is the magnitude of the net force on the particle?

+1
Answers (1)
  1. 14 September, 02:12
    0
    KE = ½ m v²

    F = m v² / r

    Therefore:

    F = 2 KE / r

    F = 2 (3.7 J) / (0.44 m)

    F ≈ 17 N
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