What change in volume results if 0.06 L of gas is cooled from 33.0 C to 5.00 C?

-0.005 L

Explanation:

Ideal gas law:

PV = nRT

where P is absolute pressure,

V is volume,

n is number of moles,

R is the gas constant,

and T is absolute temperature.

If P and n are held constant, then:

nR/P = nR/P

V/T = V/T

Given V₁ = 0.06 L, T₁ = 33.0 C = 306.15 K, and T₂ = 5.00 C = 278.15 K:

0.06 / 306.15 = V / 278.15

V = 0.055

The change in volume is:

0.055 L - 0.06 L = - 0.005 L