A Ray of light in air is incident on an air to glass boundary at an angle of 30. degrees with the normal. If the index of refraction of the glass is 1.52, what is the angle of the refracted ray within the glass with respect to the normal? A. 19 degrees B. 22 degrees C. 30 degrees D. 1.52

Question

Jesse Jordan

Physics

29 October, 16:59

A Ray of light in air is incident on an air to glass boundary at an angle of 30. degrees with the normal. If the index of refraction of the glass is 1.52, what is the angle of the refracted ray within the glass with respect to the normal? A. 19 degrees B. 22 degrees C. 30 degrees D. 1.52

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Answers (1)

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Orion Zamora · Answer 1

A

Explanation:

Snell's law states:

n₁ sin θ₁ = n₂ sin θ₂

where n is the index of refraction and θ is the angle of incidence (relative to the normal).

The index of refraction of air is approximately 1. So:

1 sin 30° = 1.52 sin θ

θ ≈ 19°