A 60-kilogram sled is coasting with a constant velocity of 10 m/s over smooth ice. It enters a rough stretch of ice 6.0 m longs in which the force of friction is 120 N. a) What is the acceleration during this stretch? B) With what speed dies it emerge from the rough patch?

Question

Brennan Wood

Physics

11 October, 16:03

A 60-kilogram sled is coasting with a constant velocity of 10 m/s over smooth ice. It enters a rough stretch of ice 6.0 m longs in which the force of friction is 120 N. a) What is the acceleration during this stretch? B) With what speed dies it emerge from the rough patch?

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Answers (1)

Know the Answer?

Londyn Gilmore · Answer 1

-2 m/s²

8.7 m/s

Explanation:

Using Newton's second law, the sum of forces in the x direction:

∑F = ma

-120 N = (60 kg) a

a = - 2 m/s²

Given:

Δx = 6.0 m

v₀ = 10 m/s

a = - 2 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (10 m/s) ² + 2 (-2 m/s²) (6.0 m)

v = 8.7 m/s