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16 December, 16:22

A rocket initially at rest acceleration at a rate of 99.0meter/second^2. Calculate the distance covered by the rocket if it attains a final velocity of 445 meters/seconds after 4.50 seconds.

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  1. 16 December, 16:51
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    Distance traveled by the rocket = 1002 m

    Explanation:

    initial velocity = Vi=0

    final velocity = V=445 m/s

    time=4.5 s

    Acceleration=a=99 m/s²

    using kinematic equation

    h = Vi t + 1/2 at²

    h = 0 (4.5) + 1/2 (99) (4.5) ²

    h=1002 m

    Thus the distance traveled by the rocket = 1002 m
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