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25 December, 09:24

A small block with mass 0.200 kg is released from rest at the top of a frictionless incline. The block travels a distance 0.202 m down the incline in 2.00 s. The 0.200 kg block is replaced by a 0.400 kg block. If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s?

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  1. 25 December, 10:56
    Answer: The block of 0.4 Kg travel the same distance that the block of

    0.2 Kg

    Explanation: Considering the second newton law, we have the following

    F = m*a

    F = P*sin (θ) where θ is the angle for the incline

    so mg sin (θ) = m*a

    a=g sin (θ)

    both block have the same acceleration in the inclined plane so travel the same distance independent of its mass.
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