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11 February, 12:26

14. Three identical light bulbs are connected in series, then are disconnected and arranged in parallel. For each of the scenarios below indicate what changes (if any) take place (1 pt. ea.):

a. Total resistance of the circuit

b. Total current of the circuit

c. Power dissipated by the circuit

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Answers (1)
  1. 11 February, 12:34
    0
    In order to make things easier to describe and explain, let's call

    the resistance of each bulb 'R', and the battery voltage 'V'.

    a). In series, the total resistance is 3R.

    In parallel, the total resistance is R/3.

    Changing from series to parallel, the total resistance of the circuit

    decreases to 1/9 of its original value.

    b). In series, the total current is V / (3R).

    In parallel, the total current is 3V / R.

    Changing from series to parallel, the total current in the circuit

    increases to 9 times its original value.

    c). In series, the power dissipated by the circuit is

    (V) · V/3R = V² / 3R.

    In parallel, the power dissipated by the circuit is

    (V) · 3V/R = 3V² / R.

    Changing from series to parallel, the power dissipated by

    the circuit (also the power delivered by the battery) increases

    to 9 times its original value.
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