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28 December, 20:14

A tennis ball is moving at a velocity of + 54 m/s before a tennis player returns it with a velocity of - 58 m/s. If the ball was in contact with her racket for 0.8 s, what was its acceleration? (Assume the acceleration was constant throughout the hit.)

A. - 140 m/s2

B. - 5 m/s2

C. 72.5 m/s2

D. 112 m/s2

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Answers (2)
  1. 28 December, 20:23
    0
    Acceleration = (change in speed) / (time for the change)

    Change in speed = (speed at the end) minus (speed at the beginning)

    Change in speed = (-58 m/s) minus (54 m/s)

    Change on speed = - 112 m/s

    Acceleration = (-112 m/s) / (0.8 s)

    Acceleration = - 140 m/s²
  2. 28 December, 20:31
    0
    a. 140 m/s2
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