Each of the two wires in a particular 16-gauge extension cord has an electric resistance of 0.0200 Ω. You're using this extension cord to operate a toaster oven, so a current of 11.0 A is flowing through it. What is the voltage drop across each wire in this extension cord?

Vd = 0.022 (V)

Explanation:

What we have as voltage drop is the difference between the voltage at source level (terminals) and the voltage at the terminal of electrical load (in this case the toaster oven) that difference occures as consequence of the normal distributed resistance of conductor. But the voltage at the terminal of the electric load have to be measure between the two wires at the end of the circuit.

Therefore the voltage drop is = I*R = 11 (A) * 0,002 Ω = 0.022 (v)