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2 June, 23:06

A 2000kg suv accelerates from rest at a rate of 3.00m/s^2. The total amount of force resisting its motion 1500N. How much force is applied to the suvs tires by the ground to make it accelerate?

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  1. 2 June, 23:30
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    The total force that the SUV exerts is:

    F = 2000 kg * 3 m/s^2

    F = 6000 N

    Since a resisting force amounting to 1500 N is exerted, then the force exerted by the SUV tires is:

    F tire = 6000 N - 1500 N

    F tire = 4500 N
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