Ask Question
13 September, 14:40

How deep would you have to go

in a mine shaft to reach a pressure

of 2.00 atm? (Assume the density

of air remains a constant

1.29 kg/m^3.)

(Unit = m)

+1
Answers (1)
  1. 13 September, 14:53
    0
    8010 m

    Explanation:

    P = Patm + ρgh

    2.00 atm = 1.00 atm + (1.29 kg/m³) (9.8 m/s²) h (9.87*10⁻⁶ atm/Pa)

    h ≈ 8010 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How deep would you have to go in a mine shaft to reach a pressure of 2.00 atm? (Assume the density of air remains a constant 1.29 kg/m^3.) ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers