How deep would you have to go

in a mine shaft to reach a pressure

of 2.00 atm? (Assume the density

of air remains a constant

1.29 kg/m^3.)

(Unit = m)

Question

13 September, 14:40

+1

Answers (1)

Know the Answer?

Ashton Galvan · Answer 1

8010 m

Explanation:

P = Patm + ρgh

2.00 atm = 1.00 atm + (1.29 kg/m³) (9.8 m/s²) h (9.87*10⁻⁶ atm/Pa)

h ≈ 8010 m

How deep would you have to goin a mine shaft to reach a pressureof 2.00 atm? (Assume the densityof air remains a constant1.29 kg/m^3.)(Unit = m)