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3 December, 22:09

An aircraft is at a standstill. It accelerates to 140kts in 28 seconds. The aircraft weighs 28,000 lbs. How many feet of runway was used?

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  1. 3 December, 22:28
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    runway use is 3307.8 feet

    Explanation:

    given data

    velocity = 140 kts = 140 * 0.5144 m/s = 72.016 m/s

    time = 28 seconds

    weight = 28000 lbs

    to find out

    How many feet of runway was used

    solution

    we will use here first equation of motion for find acceleration

    v = u + at ... 1

    here v is velocity given and u is initial velocity that is 0 and a is acceleration and t is time

    put here value in equation 1

    72.016 = 0 + a (28)

    a = 2.572 m/s²

    and

    now apply third equation of motion

    s = ut + 0.5*a*t² ... 2

    here s is distance and u is initial speed and t is time and a is acceleration

    put here all value in equation 2

    s = 0 + 0.5*2.572*28²

    s = 1008.24 m = 3307.8 ft

    so runway use is 3307.8 feet
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