Shows a 190 g hamster sitting on an 820 g wedge-shaped block. the block, in turn, rests on a spring scale. an extra-fine lubricating oil having μs=μk=0 is sprayed on the top surface of the block, causing the hamster to slide down. friction between the block and the scale is large enough that the block does not slip on the scale.

Question

Nickolas Meza

Physics

6 February, 04:25

Shows a 190 g hamster sitting on an 820 g wedge-shaped block. the block, in turn, rests on a spring scale. an extra-fine lubricating oil having μs=μk=0 is sprayed on the top surface of the block, causing the hamster to slide down. friction between the block and the scale is large enough that the block does not slip on the scale.

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Answers (1)

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Aileen Mcbride · Answer 1

The vertical component of this acceleration will be:

A = mgsin^2 θ

The downward fforce exerted by the hamster on the block and on the scle will be

F = - ma

The reading will be like this:

Reading = Mg + mg sin^2 θ

= (0.820) (9.8) + (0.190) (9.8) sin^2 (0)

Reading = 8.036 N