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11 September, 18:16

An object moves with constant acceleration 4.00 m/s^2 and over a time interval reaches a final velocity of 12.0 m/s.

a) If its initial velocity is - 6.00 m/s, what is its displacement during the time interval.

b) What is the total distance it travels during the time interval in part b?

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  1. 11 September, 18:24
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    A) We can use the equation of motion:

    2as = v² - u²

    s = (12² - (-6) ²) / 2 x 4

    s = 13.5 m

    b) We calculate the time over which this displacement occurred using:

    v = u + at

    t = (12 - - 6) / 4

    t = 4.5 seconds

    Assuming the average speed equal to:

    (12 + 6) / 2 = 9 m/s

    average speed = total distance/total time

    total distance = 9 x 4.5

    = 40.5 m
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