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1 March, 04:02

In an LC circuit containing a 40-mH ideal inductor and a 1.2-mF capacitor, the maximum charge on the capacitor is 45 mC during the oscillations. What is the maximum current through the inductor during the oscillations?

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  1. 1 March, 04:15
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    6.49A

    Explanation:

    Given the following parameters

    Inductance L = 40mH

    Capacitance C = 1.2mF

    Maximum charge on the capacitor Q = 45 mC

    The current across the inductor can be expressed as I = charge on the capacitor * angular frequency

    I = Qω where

    ω = 1/√LC

    I = Q * 1/√LC

    I = Q/√LC

    Substituting the given datas into the maximum current formula will give;

    I = 45 x 10⁻³/√ (40*10⁻³*1.2*10⁻³)

    I = 45 x 10⁻³/√48 x 10^-6

    I = 45 x 10⁻³/0.00693

    I = 0.045/0.00693

    I = 6.49A
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