The charge on a capacitor increases by 20 μC when the voltage across it increases from 84 V to 121 V. What is the capacitance of the capacitor?

Capacitance of the capacitor = 0.547 F

Explanation:

We charge of capacitor,

Q = CV

Let Q be the initial charge, we have voltage = 84 V

Q = C x 84 = 84 C

We have final charge = Q + 20.25 and voltage = 121 V

Q + 20.25 = 121 C

Substituting Q value from previous equation

84 C + 20.25 = 121 C

37 C = 20.25

C = 0.547 F

Capacitance of the capacitor = 0.547 F