Ask Question
23 June, 00:47

The ball's gravitational potential energy as a function of its height after release. The ball's kinetic energy as a function of its height after release. The ball's total mechanical energy as a function of its height after release.

+3
Answers (1)
  1. 23 June, 00:49
    0
    a) U = - G m₁m₂ / r, b) K = ½ m (v₀² + 2gy) ² or K = 2 mg² y² c) Em = m g y (2 g y + 1)

    Explanation:

    Let's write the functions that are requested

    a) Gravitational power energy

    U = - dF / dr

    F = G m₁ m₂ / r²

    U = - G m₁m₂ / r

    r is the height

    b) The scientific enrgia

    K = ½ m v²

    Cinematic

    v² = v₀² + 2 g y

    K = ½ m (v₀² + 2gy) ²

    If the initial velocity is zero, the ball is released

    K = ½ m 4 g² y²

    K = 2 mg² y²

    c) Mechanical energy

    Em = K + U

    Em = 2 m g² y² + m g y

    Em = m g y (2 g y + 1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The ball's gravitational potential energy as a function of its height after release. The ball's kinetic energy as a function of its height ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers