Mrs. Smith walks from her house 11.2 m to the grocer. Then she walks from the grocer 5.7 m to the pet store. Then she walks 32.7 m from the pet store to her daughter's house. Mrs Smith's house is directly 23.5 m away from her daughter's house. If the trip took 17 minutes what was the average velocity of Mrs. Smith?

Question

Kymani Mullins

Physics

1 February, 16:43

Mrs. Smith walks from her house 11.2 m to the grocer. Then she walks from the grocer 5.7 m to the pet store. Then she walks 32.7 m from the pet store to her daughter's house. Mrs Smith's house is directly 23.5 m away from her daughter's house. If the trip took 17 minutes what was the average velocity of Mrs. Smith?

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Answers (1)

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Ximena Molina · Answer 1

x₀ = initial position of the Mrs. smith = 0 m

since Mrs. smith finally reach her daughter's house

x = final position of Mrs. smith = 23.5 m

d = displacement of Mrs. smith

displacement of Mrs. smith is given as

d = x - x₀

inserting the values

d = 23.5 - 0

d = 23.5 m

t = time of the trip = 17 min = 17 x 60 sec = 1020 sec

average velocity of Mrs. smith is given as

V = d/t

inserting the values

V = 23.5 / 1020

V = 0.023 m/s