Ask Question
8 September, 00:04

Consider a single-slit diffraction pattern for λ=589nm, projected on a screen that is 1.00 m from a slit of width 0.25 mm. How far from the center of the pattern are the centers of the first and second dark fringes?

+4
Answers (1)
  1. 8 September, 00:13
    0
    Answer: i) 2.356 * 10^-3 m = 2.356mm, ii) 4.712 * 10^-3 m = 4.712mm

    Explanation: The formulae that relates the position of a fringe from the center to the wavelength, distance between slits and distance between slits and screen is given below as

    y = R * (mλ/d)

    Where y = distance between nth fringes and the center fringe.

    m = order of fringe

    λ = wavelength of light = 589nm = 589*10^-9m

    R = distance between slits and screen = 1.0m

    d = distance between slits = 0.25mm = 0.00025m

    For distance between the first dark fringe and the center fringe.

    This implies that m = 1

    y = 1 * 589*10^-9 * 1/0.00025

    y = 589*10^-9/0.00025

    y = 2,356,000 * 10^-9

    y = 2.356 * 10^-3 m = 2.356mm

    For the second dark fringe, this implies that m = 2

    y = 1 * 2 * 589*10^-9/0.00025

    y = 1178 * 10^-9 / 0.00025

    y = 4,712,000 * 10^-9

    y = 4.712 * 10^-3 m = 4.712mm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Consider a single-slit diffraction pattern for λ=589nm, projected on a screen that is 1.00 m from a slit of width 0.25 mm. How far from the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers