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17 December, 15:40

Frequency and velocity of a particle in simple harmonic motion Problem in that the amplitude is 0.24 in. and the maximum acceleration is 225 ft/s maximum velocity of the particle ist/s, and the frequency of its motion s z Print 20r

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  1. 17 December, 15:51
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    velocity maximum = 21.6 ft / s

    frequency = 16.88 Hz

    Explanation:

    Amplitude, A = 0.24 in = 0.02 ft

    maximum acceleration, a = 225 ft/s/

    The formula for maximum acceleration is

    a = ω² A

    225 = ω² x 0.02

    ω² = 11250

    ω = 106.06 rad/s

    Maximum velocity, v = ω A

    v = 106.06 x 0.02 = 2.1 ft/s

    Let f be the frequency

    ω = 2 x 3.14 x f

    f = 106.06 / (2 x 3.14) = 16.88 Hz
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