A 12N force is applied to a 3kg box to accelerate it from rest to 3.4m/s. How long was the force applied?

Question

Mohamed Stout

Physics

19 April, 20:10

A 12N force is applied to a 3kg box to accelerate it from rest to 3.4m/s. How long was the force applied?

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Answers (1)

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Omar Lopez · Answer 1

The formula of force is times the mass and acceleration: F = ma.

Since the acceleration is the velocity over time: a = v/t, the formula becomes

F = m * (v/t)

With F = 12 N, m = 3 kg, v = 3.4 m/s and t is unknown,

t = m * (v/F) = 3 * (3.4/12) = 0.85 seconds