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27 October, 11:05

Calculate the rate constant for the first-order decay of 24na (t1/2 = 14.7 h).

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  1. 27 October, 11:32
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    This problem is pretty straight forward since we are given the half time and we simply have to find for the rate constant. The equation relating the two variable is:

    t1/2 = ln (2) / k

    where k is the rate constant, therefore:

    k = ln (2) / t1/2

    k = ln (2) / 14.7 h

    k = 0.047 / hour
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