Ask Question
4 March, 05:31

if a bullet fired beneath the water, straight up, breaks through the surface at a speed of 25m/s, how high will the bullet be after 2.8 seconds? what is the bullet's velocity at this time? (accelaration of 9.8m/s)

+1
Answers (1)
  1. 4 March, 05:51
    0
    32 m and - 2.4 m/s

    Explanation:

    Given:

    v₀ = 25 m/s

    t = 2.8 s

    a = - 9.8 m/s²

    Find: Δy, v

    Δy = v₀ t + ½ at²

    Δy = (25 m/s) (2.8 s) + ½ (-9.8 m/s²) (2.8 s) ²

    Δy = 31.6 m

    v = at + v₀

    v = (-9.8 m/s²) (2.8 s) + 25 m/s

    v = - 2.44 m/s

    Rounded to two significant figures, the bullet reaches a height of 32 m and a velocity of - 2.4 m/s.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “if a bullet fired beneath the water, straight up, breaks through the surface at a speed of 25m/s, how high will the bullet be after 2.8 ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers