In a prototype helicopter, a jet is expelled out of the helicopter's side to make it turn in the opposite direction. If the jet supplies 10,000 N of force and the helicopter's forward speed remains at 20 m/s, what is the radius of the helicopter's turn?

Question

Mattie Mendez

Physics

23 July, 09:43

In a prototype helicopter, a jet is expelled out of the helicopter's side to make it turn in the opposite direction. If the jet supplies 10,000 N of force and the helicopter's forward speed remains at 20 m/s, what is the radius of the helicopter's turn?

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Answers (1)

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Reuben · Answer 1

The radius is (0.04m) meters

Explanation:

F = mv^2/r

m is the mass of the helicopter = m kg

v is the speed of the helicopter = 20 m/s

F is force supplied by the jet = 10,000 N

10,000 = m*20^2/r

r = 400m/10,000 = 0.04m

The radius is (0.04m) meters