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16 April, 09:53

A car from rest moves a distance s (m) in t second, where s=3t³+t²/4 determine (i) the initial acceleration of the car (ii) the acceleration of the car at the end of 3rd second

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  1. 16 April, 10:12
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    0.5, 54.5

    Explanation:

    for acceleration we should derivate the equation 2 times

    x=3t³+t²/4

    v=9t²+t/2

    a=18t+1/2

    a (0) = 0.5

    a (3) = 54.5
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