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15 December, 09:16

A spring with a constant of 350. N/m is stretched to store 210. J of energy. How much has the spring been stretched?

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  1. 15 December, 09:45
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    The formula for the potential energy of a spring is U = (1/2) kx^2. So you set U equal to 200 J, k equal to 1000 N/m, and solve for x.

    Rearranging, the equation you have to solve is x = (2U/k) ^ (1/2). So you'll get that x has to be equal to 0.632 m.
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