A ball with a mass of 2.89 kg bounces off of the ground. Just before it hits the ground, its velocity is 6.00 m/s in the downward direction. Right after it bounces, its velocity is 4.54 m/s in the upward direction. What is the magnitude of the impulse J that the ground gave the ball? Give your answer in kg m/s with an accuracy of 0.1 kg m/s.

Question

Kymani Woodard

Physics

15 December, 22:16

A ball with a mass of 2.89 kg bounces off of the ground. Just before it hits the ground, its velocity is 6.00 m/s in the downward direction. Right after it bounces, its velocity is 4.54 m/s in the upward direction. What is the magnitude of the impulse J that the ground gave the ball? Give your answer in kg m/s with an accuracy of 0.1 kg m/s.

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Answers (1)

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Quinn · Answer 1

30.46 kgm/s

Explanation:

According to conservation law of momentum, the magnitude of the impulse J that the ground gave the ball equals to the change in momentum of the ball before and after it hits the ground.

Before the hit, the ball velocity is 6m/s, so its momentum is 6 * 2.89 = 17.34 kgm/s

After the hit, the ball velocity is - 4.54 m/s in the opposite direction, so its momentum is 2.89 * (-4.54) = - 13.12 kgm/s

So the change of momentum, and also the impulse is

17.34 - (-13.12) = 30.46 kgm/s