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30 November, 20:38

What is the longest wavelength of radiation that possesses the necessary energy to break the bond 941?

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  1. 30 November, 20:45
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    Energy is calculated by molecule dividing energy by mole by Avogadro's number (6.022*10^23) 941kJ=9.41*10^5 J so energy by molecule E = 9.41*10^5/6.022*10^23=1.563*10^-18 J Wavelength (w) given by E=hc/w where, E = energy h = planks constant (6.6262 x 10-34 J·s) c = speed of light (3 x 10^8 m/s) So, w = hc/E = (6.6262*10^-34) * (3*10^8) / 1.563*10^-18 = 127.2 Nm Longest wavelength of radiation = 127.2 Nm
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