How much heat is absorbed by a 74g iron skillet when its temperature rises from 7oC to 28oC?

The specific heat of iron (assuming the skillet is pure iron) is 0.45 J/g-C. Then we use the equation q = mc (dT) to determine the total heat absorbed. This gives:

q = (74 g) (0.45 J/g-C) (28 - 7 C) = (74) (0.45) (21) = 699.3 J