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10 April, 02:36

A 4.25 g bullet traveling horizontally with a velocity of magnitude 375 m/s is fired into a wooden block with mass 1.10 kg, initially at rest on a level frictionless surface. The bullet passes through the block and emerges with its speed reduced to 122 m/s.

How fast is the block moving just after the bullet emerges from it?

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  1. 10 April, 02:46
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    block is moving at 0.97m/s after the bullet emerges from it

    Explanation:

    The problem is based on elastic collision

    Given data

    Mass of bullet m1 = 4.25g to kg we have 4.25/1000 = 0.00425kg

    Mass of block m2 = 1.10kg

    Initial velocity of bullet u1 = 375m/s

    Initial velocity of block u2 = 0m/s

    Final velocity of bullet v1 = 122m/s

    Final velocity of block v2=?

    To solve for the final velocity of the block let us apply the principles of conservation of momentum for an elastic collision

    m1u1+m2u2=m1v1+m2v2

    Substituting our data into the

    expression we have

    (4.25*10^-3*375) + (1.1*0) =

    (4.25*10^-3*122) + (1.1*v2)

    1.59+0=0.52+1.1v2

    1.59-0.52=1.1v2

    1.07=1.1v2

    v2=1.07/1.1

    v2 = 0.97m/s
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